Under pure rolling condition: v=ωR
Translational K.E=21mv2
Rotational K.E=21×52mR2(Rv)2=51mv2
Total K.E=21mv2+51mv2=107mv2
So, TotalK⋅ERotationalK⋅E=107mv251mv2=72
A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is
Held on 26 Jun 2022 · Verified 6 Jul 2026.
51
52
72
107
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