a=mF=0.110i^+5j^=100i^+50j^
Displacement covered in vector form can be written as, s=ut+21at2
⇒s=21(100i^+50j^)(2)2
, ⇒s=200i^+100j^
Comparing it with, s=ai^+bj^, we get a=200\text{&}b=100
Therefore, ba=2
A force on an object of mass 100g is (10i^+5j^)N. The position of that object at t=2s is (ai^+bj^)m after starting from rest. The value of ba will be _____ .
Held on 25 Jun 2022 · Verified 6 Jul 2026.
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