In both, cases is about point of contact ring,
mgh=21Iω2
mgh=21(2mR2)R2VR2
VR=gh
Solid cylinder
mgh=21Iω2
mgh=21(23mR2)R2vC2
vC=34gh
vCvR=23
JEE Main 2021 — Physics Mechanics
Two bodies, a ring and a solid cylinder of same material are rolling down without slipping an inclined plane. The radii of the bodies are same. The ratio of velocity of the centre of mass at the bottom of the inclined plane of the ring to that of the cylinder is 2x. Then, the value of x is
Held on 20 Jul 2021 · Verified 6 Jul 2026.
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