q=CV
[C]=[Vq]=ML2T−2(A×T)2
=M−1L−2T4A2
[E]=[qF]=ATMLT−2
=MLT−3A−1
F=4π∈0r2q1q2
[ϵo]=M−1L−3T4A2
Speed of light c=μ0∈o1
μ0=ϵ0c21
[μ0]=[M−1L−3T4A2][LT−1]21
=[M1L1T−2A−2]
Match List I with List II. List-I List-II a Capacitance, C i M^1 L^1 T^-3 A^-1 b Permittivity of free space, ε _0 ii M^-1 L^-3 T^4 A^2 c Permeability…
JEE Main 2021 — Physics Mechanics
2021mcqmedium
Match List I with List II.
| List-I | List-II | ||
| a | Capacitance, C | i | M1L1T−3A−1 |
| b | Permittivity of free space, ϵ0 | ii | M−1L−3T4A2 |
| c | Permeability of free space, μ0 | iii | M−1L−2T4A2 |
| d | Electric field, E | iv | M1L1T−2A−2 |
Official previous-year question
Held on 27 Jul 2021 · Verified 6 Jul 2026.
Options
- A
(a)→(iii),(b)→(ii),(c)→(iv),(d)→(i)
- B
(a)→(iii),(b)→(iv),(c)→(ii),(d)→(i)
- C
(a)→(iv),(b)→(ii),(c)→(iii),(d)→(i)
- D
(a)→(iv),(b)→(iii),(c)→(ii),(d)→(i)
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Mechanics in other years
More JEE Main Mechanics questions
If $\epsilon, E$ and $t$ represent the free space permittivity, electric field and time respectively, then the unit of $\frac{\epsilon E}{t}$ will be :
2026easy
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height $h$. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by $1 \%$ each, then the height of the liquid in the tube will change by $\%$.
2026medium
The velocity of a particle is given as $\vec{v} = -x\hat{i} + 2y\hat{j} - z\hat{k}$ m/s. The magnitude of acceleration at point $(1, 2, 4)$ is _______ m/s$^2$.
2026hard
Suppose there is a uniform circular disc of mass $M \mathrm{~kg}$ and radius $r \mathrm{~m}$ shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis $A$ of the disc is given by $\frac{x}{256} M r^{2}$. The value of $x$ is $\_\_\_\_$. 
2026hard
A soap bubble of surface tension $0.04 \mathrm{~N} / \mathrm{m}$ is blown to a diameter of 7 cm. If $(15000-x) \mu \mathrm{J}$ of work is done in blowing it further to make its diameter 14 cm, then the value of $x$ is $\_\_\_\_$. ($\pi=22 / 7$)
2026medium
Other Physics topics for JEE Main
Keep practicing Mechanics
Work through every JEE Main Mechanics PYQ, year by year.