[M]1=[V]a[T]b[F]c
[M]1=[LT−1]a[T]b[MLT−2]c
[M]1=[M]c[L]a+c[T]−a+b−2c
Thus,
c=1,a+c=0and⇒a=−1b−a−2c=0⇒b=−1+2=1
Thus, [M]=[V]−1[T]1[F]1
If velocity [V] time [T] and force [F] are chosen as the base quantities, the dimensions of the mass will be :
Held on 31 Aug 2021 · Verified 6 Jul 2026.
[FVT−1]
[FT−1V−1]
[FT2V]
[FTV−1]
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