Moment of inertia of point mass = mass × (Perpendiculardistancefromaxis)2

Moment of Inertia
=m(0)2+m(l2)2+m(2l)2+m(2l)2
=3ml2
JEE Main 2021 — Physics Mechanics
Four equal masses, m each are placed at the corners of a square of length (l) as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to DB would be :

Held on 16 Mar 2021 · Verified 6 Jul 2026.
ml2
2ml2
3ml2
3ml2
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