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A particle is projected with velocity v_0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance…

JEE Main 2021 — Physics Mechanics

2021mcqhard

A particle is projected with velocity v0{v}_{0}v0​ along xxx-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma=−αx2.ma=-\alpha {x}^{2}.ma=−αx2. The distance at which the particle stops:

Official previous-year question

Held on 24 Feb 2021 · Verified 6 Jul 2026.

Options

  1. A

    (2v03α)13{(\frac{2{v}_{0}}{3\alpha })}^{\frac{1}{3}}(3α2v0​​)31​

  2. B

    (3mv022α)13{(\frac{3m{v}_{0}^{2}}{2\alpha })}^{\frac{1}{3}}(2α3mv02​​)31​

  3. C

    (3v022α)12{(\frac{3{v}_{0}^{2}}{2\alpha })}^{\frac{1}{2}}(2α3v02​​)21​

  4. D

    (2v023α)12{(\frac{2{v}_{0}^{2}}{3\alpha })}^{\frac{1}{2}}(3α2v02​​)21​

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