The equation of the straight line, y=mx+c, from the above graph we get the equation, v2=2x+20, now differentiate it with respect to x,
⇒2vdxdv=2⇒a=22=1ms−2.
A particle is moving with constant acceleration a. Following graph shows v2 versus x (displacement) plot. The acceleration of the particle is _________ ms−2.

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Net gravitational force at the center of a square is found to be $F_{1}$ when four particles having mass $M, 2 M, 3 M$ and $4 M$ are placed at the four corners of the square as shown in figure and it is $F_{2}$ when the positions of $3 M$ and $4 M$ are interchanged. The ratio $\frac{F_{1}}{F_{2}}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$. 
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