2m×40=60×m+mv
V=20m/s
Now ΔKE=KEf−KEi=21m×(20)2+21m×(60)2−212m×(40)2
ΔKE=21m(800)⇒KEi=212m×(40)2=21m×3200
Fractional change =KEiΔKE=41
A block moving horizontally on a smooth surface with a speed of 40ms−1 splits into two equal parts. If one of the parts moves at 60ms−1 in the same direction, then the fractional change in the kinetic energy will be x:4 where x= ________.
Held on 31 Aug 2021 · Verified 6 Jul 2026.
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