VMA=−1.8kmhr−1=−0.5ms−1
Vman,B=Vman,A+VA,B
=Vman,A+VA−VB
=−0.5+10−(−20)
=−0.5+30
=29.5ms−1
Train A and train B are running on parallel tracks in the opposite directions with speed of 36kmhour−1 and 72kmhour−1, respectively. A person is walking in train A in the direction opposite to its motion with a speed of 1.8kmhour−1. Speed (inms−1) of this person as observed from train B will be close to: (take the distance between the tracks as negligible)
Held on 2 Sept 2020 · Verified 6 Jul 2026.
29.5ms−1
28.5ms−1
31.5ms−1
30.5ms−1
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