Given that
gn=gd
(R+h)2GM=R3GM(R−d)
(R+R/2)2GM=R3GM(R−d)
9R24GM=R2GM(1−Rd)
94=1−Rd
Rd=1−94=95
d=95R
The value of the acceleration due to gravity is g1 at a height h=2R (R= radius of the earth) from the surface of the earth. It is again equal to g1 at a depth d below the surface the earth. The ratio (Rd) equals:
Held on 5 Sept 2020 · Verified 6 Jul 2026.
94
95
31
97
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