Equation (1)
Sx=21axt2
20=21×10×t2
t=2
Equation (2)
Sy=uyt+21ayt2
y=5(2)+21(4)(2)2
y=18
JEE Main 2020 — Physics Mechanics
Starting from the origin at time t=0, with initial velocity 5j⏜ms−1, a particle moves in the x -y plane with a constant acceleration of (10i⏜+4j⏜)ms−2. At time t, its coordinates are (20m, y0 m). The values of t and y0 are, respectively:
Held on 4 Sept 2020 · Verified 6 Jul 2026.
2s and 18 m
4s and 52 m
2s and 24 m
5s and 25 m
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