m1u1+m2u2=m1v1+m2v2
2m2(3i^+j^)+m2×0=2m2(i^+3j^)+m2×v2
23i^+2j^=2i^+23j^+v2
v2=(3−1)i^−(3−1)j^
v1=i^+3j^
Angle between v1 and v2 is 105∘

Particle A of mass m1 moving with velocity (3i^+j^)ms−1 collides with another particle B of mass m2 which is at rest initially. Let v1 and v2 be the velocities of particles A and B after collision respectively. If m1=2m2 and after collision v1−(i^+3j^)ms−1, the angle between v1 and v2 is :
Held on 6 Sept 2020 · Verified 6 Jul 2026.
15∘
60∘
−45∘
105∘
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