Y∝FaVbAcY=(AF)
L2MLT−2∝(M1L1T−2)a(L1T−1)b(L2)c
M1L−1T−2∝MaLa+b+2cT−2a−b
a+b+2c=–1
–2a+b=–2
a=1,b=0,c=–1
Y=F1V0A−1
If speed V, area A and force F are chosen as fundamental units, then the dimension of Young's modulus will be :
Held on 2 Sept 2020 · Verified 6 Jul 2026.
FA2V−1
FA2V−3
FA2V−2
FA−1V0
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