Net force on motor will be
Fm=[920+68(10)]g+6000
=22000N
So, required power for motor
Pm=Fm.v
=22000×3
=66000watt
JEE Main 2020 — Physics Mechanics
An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68kg . The mass of the elevator itself is 920kg and it moves with a constant speed of 3m/s . The frictional force opposing the motion is 6000N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g=10m/s2) must be at least:
Held on 7 Jan 2020 · Verified 6 Jul 2026.
56300W
62360W
48000W
66000W
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