
Xa=A−A1A⋅X−A⋅X1=πa2−4a2πa2×0−4a2×2a
=(π−41)a2−a3/8=2(4π−1)−a=8π−2−a=−23a
x=23
A square shaped hole of sidel=2a is carved out at a distance d=2a from the centre 'O' of a uniform circular disk of radius a. If the distance of the centre of mass of the remaining portion from O is −xa, value of X (to the nearest integer) is :

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