v1=(8−6t)i^
v2=(−24t2)j^
∣v21∣=580
A particle is moving along the x -axis with its coordinate with time t given by x(t)=10+8t−3t2. Another particle is moving along the y -axis with its coordinate as a function of time given by y(t)=5−8t3. At t=1s, the speed of the second particle as measured in the frame of the first particle is given as v. Then v(inms−1) is ___________.
Held on 8 Jan 2020 · Verified 6 Jul 2026.
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Work through every JEE Main Mechanics PYQ, year by year.