In equilibrium mg=FB
34π(R3−r3)ρ0g=34πR3ρwg
[1−(Rr)3]827ρw=ρw
1−R3r3=279
1−31=R3r3
32=R3r3
Rr=(32)1/3
1−R3r3=278
R3r3=1−278=2719
r=0.89
JEE Main 2020 — Physics Mechanics
A hollow spherical shell at outer radius R floats just submerged under the water surface. The inner radius of the shell is r. If the specific gravity of the shell material is 827 with respect to water, the value of r is:
Held on 5 Sept 2020 · Verified 6 Jul 2026.
98R
94R
32R
31R
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