B=−VΔVΔP
VΔV=−BΔP
Magnitude is given by,
∣VΔV∣=BΔP
Volume in terms of length can be represented as,
3×∣LΔL∣=BΔP
Therefore,
∣LΔL∣=31×BΔP
Substituting the values we get,
∣LΔL∣=31×8×10104×109=601
Percantage change is,
601×100=35=1.67
A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to : (Given bulk modulus of metal, B=8×1010Pa)
Held on 4 Sept 2020 · Verified 6 Jul 2026.
5
0.6
20
1.67
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