Using the principle of conservation of linear momentum
0.1×3i^+0.1×5j^=0.1×4(i^+j^)+0.1×v
v=(−i^+j^)ms−1
v=∣v∣=2ms−1
KB=21×0.1×v2=101J
x=1
A body A of mass m=0.1kg has an initial velocity of 3i^ms−1. It collides elastically with another body B of the same mass which has an initial velocity of 5j^ms−1. After the collision, A moves with a velocity v=4(i^+j^)ms−1. The energy of B after the collision is written as 10xJ. The value of x is
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