Maximum possible acceleration of 1kg block a=mμmg=μg=2m/s2
For 1g block not to slide the maximum acceleration of both blocks should be
Fmax−μmg=mamax
Fmax−0.2×4×10=4×2
Fmax−8=8
Fmax=16N
Two blocks A and B of masses m_A=1 kg and m_B=3 kg are kept on the table as shown in figure. The coefficients of friction between A and B is 0.2 and…
JEE Main 2019 — Physics Mechanics
2019mcqmedium
Two blocks A and B of masses mA=1kg and mB=3kg are kept on the table as shown in figure. The coefficients of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is : [Take g=10m/s2 ]
Official previous-year question
Held on 10 Apr 2019 · Verified 6 Jul 2026.
Options
- A
16N
- B
12N
- C
40N
- D
8N
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