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The resistance of the meter bridge AB in given figure is 4 Ω. With a cell of emf ε=0.5 ~V and rheostat resistance R_ h=2 Ω the null point is obtained…

JEE Main 2019 — Physics Mechanics

2019mcqhard

The resistance of the meter bridge AB in given figure is 4Ω4 \Omega4Ω. With a cell of emf ε=0.5 V\varepsilon=0.5 \mathrm{~V}ε=0.5 V and rheostat resistance Rh=2Ω\mathrm{R}_{\mathrm{h}}=2 \OmegaRh​=2Ω the null point is obtained at some point J. When the cell is replaced by another one of emf ε=ε2\varepsilon=\varepsilon_{2}ε=ε2​ the same null point J\mathrm{J}J is found for Rh=6Ω\mathrm{R}_{\mathrm{h}}=6 \OmegaRh​=6Ω. The emf⁡ε2\operatorname{emf} \varepsilon_{2}emfε2​ is: JEE Main 2019 Physics, Experimental Physics — question figure

Official previous-year question

Held on 11 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    0.4 V0.4 \mathrm{~V}0.4 V

  2. B

    0.3 V0.3 \mathrm{~V}0.3 V

  3. C

    0.6 V0.6 \mathrm{~V}0.6 V

  4. D

    0.5 V0.5 \mathrm{~V}0.5 V

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