x(t)=at+bt2−ct3
velocity v(t)=dtd(x)=dtd(at+bt2−ct3)
=a+2bt−3ct2
Acceleration =dtdv(t)=2b−6tc
acceleration=0⇒2b−6tc=0
t=3cb
∴ velocity when t=3cb,
v(t=3cb)=a+2b(3cb)−3(3cb)2
=a+3c2b2−3cb2
=a+3cb2
The position of a particle as a function of time t, is given by x(t)=at+bt2−ct3 where a,b and c are constants. When the particles zero acceleration, then its velocity will be:
Held on 9 Apr 2019 · Verified 6 Jul 2026.
a+3cb2
a+2cb2
a+cb2
a+4cb2
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