V=4πd2h=4π(12.6)2(34.2)cm3
VdV=d2d(d)+hd(h)
Converting to errors
VΔV=2dΔd+hΔh
4260ΔV=2(12.60.1)+(34.20.1)
⇒ΔV=80cm3
V=4260±80cm3
The diameter and height of a cylinder are measured by a meter scale to be 12.6±0.1cm and 34.2±0.1cm , respectively. What will be the value of its volume in appropriate significant figures?
Held on 10 Jan 2019 · Verified 6 Jul 2026.
4264±81cm3
4264.4±81.0cm3
4260±80cm3
4300±80cm3
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