Case-1, σVg=ρw54Vg …….(I)
Case-2, σVg=ρw2Vg+ρo2Vg …….(II)
From eq (I) & (II),
54ρw=2ρw+2ρo
(54−21)ρw=2ρo
(108−5)ρw=2ρo
ρwρo=53=0.6
A wooden block floating in a bucket of water has 54 of its volume submerged. When certain amount of an oil is poured into the bucket, it is found that the block is just under the oil surface with half of its volume under water and half in oil. The density of oil relative to that of water is:
Held on 9 Apr 2019 · Verified 6 Jul 2026.
0.8
0.7
0.5
0.6
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