
F=∫aa+Lx2GmdM=Gm∫aa+Lx2(A+Bx2)dx
=Gm[∫aa+Lx2Adx+∫aa+LBdx]
=Gm[A[x−1]aa+L+BL]
=Gm[A(a1−a+L1)+BL]
A straight rod of length L extends from x=a to x=L+a. The gravitational force it exerts on a point mass 'm' at x=0, if the mass per unit length of the rod is A+Bx2, is given by:
Held on 12 Jan 2019 · Verified 6 Jul 2026.
Gm[A(a+L1−a1)+BL]
Gm[A(a+L1−a1)−BL]
Gm[A(a1−a+L1)−BL]
Gm[A(a1−a+L1)+BL]
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