Kinetic Energy =kθ2
21Iω2=kθ2
ω2=I2kθ2
Differentiate both side w.r.t. θ .
2ωdθdω=I4kθ
ωdθdω=I2kθ
α=I2kθ
A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as kθ2. If its moment of inertia is I then the angular acceleration of the disc is:
Held on 9 Apr 2019 · Verified 6 Jul 2026.
I2kθ
2Ikθ
4Ikθ
Ikθ
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