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A particle of mass 20 g is released with an initial velocity 5 ms^-1 along the curve from the point A, as shown in the figure. The point A is at…

JEE Main 2019 — Physics Mechanics

2019mcqmedium

A particle of mass 20g20 g20g is released with an initial velocity 5ms−15 m{s}^{-1}5ms−1 along the curve from the point A,A,A, as shown in the figure. The point AAA is at height hhh from point B.B.B. The particle slides along the frictionless surface. When the particle reaches point B,B,B, its angular momentum about OOO will be: (Take g=10ms−2g=10 m{s}^{-2}g=10ms−2)

JEE Main 2019 Physics, Work Power Energy — question figure

Official previous-year question

Held on 12 Jan 2019 · Verified 6 Jul 2026.

Options

  1. A

    3kgm2s−13 \mathrm{kg}{m}^{2}{s}^{-1}3kgm2s−1

  2. B

    2kgm2s−12 \mathrm{kg}{m}^{2}{s}^{-1}2kgm2s−1

  3. C

    6kgm2s−16 \mathrm{kg}{m}^{2}{s}^{-1}6kgm2s−1

  4. D

    8kgm2s−18 \mathrm{kg}{m}^{2}{s}^{-1}8kgm2s−1

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