From Newton's second law dtdp=F=kt Integrating both sides we get, ∫p3pdp=∫0Tktdt⇒[p]p3p=k[2t2]0T ⇒2p=2kT2⇒T=2kp
A particle of mass m is moving in a straight line with momentum p. Starting at time t=0, a force F=k t acts in the same direction on the moving particle during time interval T so that its momentum changes from p to 3p. Here k is a constant. The value of T is
Held on 11 Jan 2019 · Verified 6 Jul 2026.
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Net gravitational force at the center of a square is found to be $F_{1}$ when four particles having mass $M, 2 M, 3 M$ and $4 M$ are placed at the four corners of the square as shown in figure and it is $F_{2}$ when the positions of $3 M$ and $4 M$ are interchanged. The ratio $\frac{F_{1}}{F_{2}}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$. 
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