x=x0+acos(ω1t)
y=y0+bsin(ω2t)
ax=−aω12cos(ω1t)
ay=−bω22sin(ω2t)
At t=0 ,
F=ma=(−aω12i^)
And
r=(x0+a)i^+y0j^
Torque, τ=r×F
τ=((x0+a)i^+y0j^)×(−aω12i^)
=my0aω12k^
A particle of mass m is moving along a trajectory given by
x=x0+acosω1t
y=y0+bsinω2t
The torque, acting on the particle about the origin, at t=0 is:
Held on 10 Apr 2019 · Verified 6 Jul 2026.
+my0aω12k^
−m(x0bω22−y0aω12)k^
Zero
m(−x0b+y0a)ω12k^
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