δ=Ayρ0vg×L
{\delta }^{'}=\frac{({\rho }_{0}-{\rho }_{L})vg\times L}{Ay}\Rightarrow \frac{\delta ^'}{\delta }=\frac{{\rho }_{0}-{\rho }_{L}}{{\rho }_{0}}=\frac{8-2}{8}
δ′=3mm
JEE Main 2019 — Physics Mechanics
A load of mass Mkg is suspended from a steel wire of length 2m and radius 1.0mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0mm. Now the load is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8. The new value of increase in length of the steel wire is:
Held on 12 Jan 2019 · Verified 6 Jul 2026.
4.0mm
Zero
5.0mm
3.0mm
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