Moment of inertia of disc D1 about OO′=I1=2MR2 M.O.I of D2 about OO′ =I2=21(2MR2)+MR2=4MR2+MR2 M.O.I of D3 about OO′ =I3=21(2MR2)+MR2=4MR2+MR2 so, resultant M.O.I about OO′ is I=I1+I2+I3 ⇒I=2MR2+2(4MR2+MR2)=2MR2+2MR2+2MR2=3MR2
A circular disc D1 of mass M and radius R has two identical discsD2 and D3 of the same mass M and radius R attached rigidly at its opposite ends (see figure). The moment of inertia of the system about the axis OO', passing through the centre of D1, as shown in the figure, will be 
Held on 11 Jan 2019 · Verified 6 Jul 2026.
MR2
3MR2
54MR2
32MR2
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