F1=r13GMem,F2=r22GMeMs
ΔF1=(−)r132GMemΔr1,ΔF2=(−)r222GMeMsΔr2
ΔF2ΔF1=r13mΔr1MsΔr2r23=(Msm)(r13r23)(Δr2Δr1)
Using Δr1=Δr2=2Rearth
m=8×1022kg
Ms=2×1030kg
r1=0.4×106km
r2=150×106km
We get ΔF2ΔF1=2.
JEE Main 2018 — Physics Mechanics
Take the mean distance of the moon and the sun from the earth to be 0.4×106km and 150×106km, respectively. Their masses are 8×1022 kg and 2×1030 kg, respectively. The radius of the earth is 6400km. Let ΔF1 be the difference in the forces exerted by the moon at the nearest and farthest point on the earth, and ΔF2 be the difference in the forces exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to ΔF2ΔF1 is,
Held on 15 Apr 2018 · Verified 6 Jul 2026.
6
10−2
2
0.6
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