According to question, u1=40 km/h,v1=0 and s1=40 m using v2−u2=2as;02−402=2a×40..(i) Again, 02−802=2 as From eqn. (i) and (ii) Stopping distance, s=160 m
An automobile, travelling at 40 km/h, can be stopped at a distance of 40 m by applying brakes. If the same automobile is travelling at 80 km/h, the minimum stopping distance, in metres, is (assume no skidding)
Held on 15 Apr 2018 · Verified 6 Jul 2026.
75 m
160 m
100 m
150 m
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