dtdV=8πηLpr4
L1p1r14=L2p2r24
l1p1r14=(4l1)4p1r24
⇒r24=16r14
⇒r2=2r1
JEE Main 2017 — Physics Mechanics
Two tubes of radii r1 and r2 and lengths l1 and l2, respectively, are connected in series and a liquid flows through each of them in stream line conditions. P1 and P2 are pressure differences across the two tubes. If P2 is 4P1 and l2 is 4l1 then the radius r2 will be equal to :
Held on 9 Apr 2017 · Verified 6 Jul 2026.
4r1
r1
2r1
2r1
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