Given, l=1m, r=5×10−3m and F=50π×103N.
Least count in length is =0.01mm=0.01×10−3m
Young's modulus is given by Y=lΔlAF
For, Δl→Min, Y→Max
⇒YlΔl=AF
Y=π×(5×10−3)250π×103×Δll
Y=25×10−650×103×Δl1⇒Y=Δl2×109
Here Δl is unknown so we can not find the Y
The change in young’s modulus ratio is YΔY=2rΔr+lΔl.
As seen from above, the minimum contribution to change in young’s modulus is given by the uncertainty in the length and the maximum contributing to the uncertainty in young’s modulus is given by uncertainty in radius.
Hence, correct option is A.