| T | Ts | Ti−T |
|---|---|---|
| t1 | 90 | - 2 |
| t2 | 91 | - 1 |
| t3 | 95 | 3 |
| t4 | 92 | 0 |
| Ti | 92 | NΣ∣Ti−T∣=1.5 |
Tr=92±1.5
Tr=92±2
Because least count of clock is 1s
A student measures the time period of 100 oscillations of a simple pendulum four times. The data set is 90 s, 91 s, 95 s and 92 s. If the minimum division in the measuring clock is 1 s, then the reported mean time should be:
Held on 3 Apr 2016 · Verified 6 Jul 2026.
92±1.8s
92±3s
92±2s
92±5.0s
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