
From free body diagram of cylinder
F−fs=ma .....(1)
∵∑fext=macm
also∑τext=Icmα
⟹fsR=Icmα
⟹fsR=21mR2α ..... (2)
For rolling without slipping

a=Rα ...... (3)
⟹α=Ra
∴fsR=21mR2Ra
⟹fs=21ma
Put in (1)
F−21ma=ma
⟹F=23ma
A uniform solid cylindrical roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:
Held on 10 Apr 2015 · Verified 6 Jul 2026.
23ma
2ma
35ma
ma
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