Force F=αr2 will act as centripetal force
⇒αr2=rmv2⇒mv2=αr3
∴ Kinetic energy K.E.=21mv2
⇒K.E.=2αr3
Also dU=−F.dr
ΔU=−∫F.dr
=−∫αr2(−dr)
=α∫0rr2dr
U−0=3αr3
⇒U=3αr3
So total mechanical energy
E=U+K
=3αr3+2αr3
E=65αr3
JEE Main 2015 — Physics Mechanics
A particle is moving in a circle of radius r under the action of a force F=αr2 which is directed towards centre of the circle. Total mechanical energy (kinetic energy + potential energy) of the particle is (take potential energy=0 for r=0):
Held on 11 Apr 2015 · Verified 6 Jul 2026.
65αr3
αr3
21αr3
34αr3
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