
From question, Horizontal velocity (initial),
ux=240=20m/s
Vertical velocity (initial), 50=uyt+21gt2
⇒50=uy×2+21(−10)×4
50=2uy−20
uy=270=35m/s
∴tanθ=uxuy=2035=47
⇒ θ=tan−147
The position of a projectile launched from the origin at t = 0 is given by r=(40i^+50j^)m at t = 2s. If the projectile was launched at an angle θ from the horizontal, then θ is (take g = 10 ms−2).
Held on 9 Apr 2014 · Verified 6 Jul 2026.
tan−123
tan−132
tan−147
tan−154
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