6vA=10vB......(1)
21ρvA2−ρgh=21ρvB2 .........(2)
⇒vA=0.81ms−1
dtdV=AvA
=6×10−2cm2×0.8100cms−1=7.5ccs−1
OR
By the concept of the venturi meter tube
rate of flow=Q=A1A2(A22−A12)2g(h1−h2)
=6×10×10−4(−36+100)×10−22×100×5
=7.5ccs−1

In the diagram shown, the difference in the two tubes of the manometer is 5cm, the cross-section of the tube at A and B is 6mm2 and 10mm2 respectively. The rate at which water flows through the tube is (g=10ms−2)
Held on 19 Apr 2014 · Verified 6 Jul 2026.
7.5ccs−1
12.5ccs−1
8.0ccs−1
10.0ccs−1
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