From question, Mass of body, m=5 kg Velocity at t=0, u=(6i^−2j^)m/s Velocity at t=10 s, v=+6j^ m/s Force, F= ? Acceleration, a=tv−u =106j^−(6i^−2j^)=5−3i^+4j^ m/s2 Force, F=ma =5×5(−3i^+4j^)=(−3i^+4j^)N
A body of mass 5 kg under the action of constant force F=Fxi^+Fyj^ has velocity at t=0 s as v=(6i^−2j^m/s) and at t=10 s as v=+6j^m/s. The force F is:
Held on 11 Apr 2014 · Verified 6 Jul 2026.
(−3i^+4j^)N
(−53i^+54j^)N
(3i^−4j^)N
(53i^−54j^)N
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