Range is same for both holes ∴2(H−h1)h1=2(H−h2)h2 Squaring both sides, 4(H−h1)h1=4(H−h2)h2Hh1−h12=Hh2−h22 On solving we get, H=h1+h2 Hence, the ratio of h2h1 depends on H.
In a cylindrical water tank, there are two small holes A and B on the wall at a depth of h1, from the surface of water and at a height of h2 from the bottom of water tank. Surface of water is at height of h2 from the bottom of water tank. Surface of water is at heigh H from the bottom of water tank. Water coming out from both holes strikes the ground at the same point S. Find the ratio of h1 and h2 
Held on 26 May 2012 · Verified 6 Jul 2026.
Depends on H
1:1
2:2
1:2
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