If it is a completely inelastic collision then m1v1+m2v2=m1v+m2vv=m1+m2m1v1+m2v2 K⋅E=2 m1p12+2 m2p22 as p1 and p2 both simultaneously cannot be zero therefore total KE cannot be lost.
Statement-1 : Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement-2 : Principle of conservation of momentum holds true for all kinds of collisions. Of the four choices given after the statements, choose the one that best describes the two statements. Of the four choices given after the statements, choose the one that best describes the two statements.
Held on 30 Apr 2010 · Verified 6 Jul 2026.
Statement-1 is true, Statement-2 is true; Statement-2 is the correct explanation of Statement-1.
Statement-1 is true, Statement-2 is true; Statement-2 is not the correct explanation of Statement1
Statement-1 is false, Statement-2 is true.
Statement-1 is true, Statement-2 is false.
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