Ph−CH=CH2(PhCOO)2HBrPh−CH2−CH2−Br
Anti Markovnikov addition
• Reaction follow radical addition in presence of peroxide
• In absence of peroxide follow carbocation mechanism
• Benzene also formed
Ph- CH= CH_2 xrightarrow[ HBr]( PhCOO)_2 Product Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B.…
JEE Main 2026 — Chemistry Organic Chemistry
2026mcqmedium
Ph−CH=CH2(PhCOO)2HBr Product
Consider the above reaction
A. The reaction proceeds through a more stable radical intermediate.
B. The role of peroxide is to generate H∘ (Hydrogen radical).
C. During this reaction, benzene is formed as a byproduct.
D. 1-Bromo-2-phenylethane is formed as the minor product.
E. The same reaction in absence of peroxide proceeds via carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below:
Official previous-year question
Held on 28 Jan 2026 · Verified 6 Jul 2026.
Options
- A
C, D & E Only
- B
A, B & D Only
- C
A, C & E Only
- D
A & E Only
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