Organic Compound ⟶0.20gmBaSO40.40gm2330.40 mol(BaSO4)2330.40 mol (Sulphur) 2330.40×32gm (sulphur) % S=0.202330.40×32×100=27.5% or 275×10−1%
In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ ×10−1%. (Molar mass : O=16, S=32,Ba=137 in gmol−1 )
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Consider the following reaction sequence  Compound $(\mathrm{y})$ develops characteristic colour with neutral $\mathrm{FeCl}_{3}$ solution. Identify the INCORRECT statement from the following for the above sequence.
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