Partial pressure of N2=(900−15)=885 mmHg
Mole of N2=(0.0821×300)(760885×0.15)=0.0071
Moles % of nitrogen in organic compound
$\begin{aligned}
& =\frac{(0.0071 \times 28)}{1} \times 10 \
& =19.85 %
\end{aligned}$
In Dumas' method for estimation of nitrogen 1 g of an organic compound gave 150 mL of nitrogen collected at 300 K temperature and 900 mm Hg pressure. The percentage composition of nitrogen in the compound is _____ % (nearest integer).
(Aqueous tension at 300 K=15 mmHg)
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