CH3−C≡CH+Na→CH3−C≡C−Na++21H2 Statement-l is correct. Moles of C3H4=404=0.1 mole CH3−C≡CH+NaNH2→CH3−C≡C−Na++NH3 0.1 mole 0.1 mole Volume of NH3=(0.1)(22.4)=2.24 L Statement-II is incorrect.
Given below are two statements : Statement I : One mole of propyne reacts with excess of sodium to liberate half a mole of H_2 gas. Statement II :…
JEE Main 2025 — Chemistry Organic Chemistry
2025mcqmedium
Given below are two statements : Statement I : One mole of propyne reacts with excess of sodium to liberate half a mole of H2 gas. Statement II : Four g of propyne reacts with NaNH2 to liberate NH3 gas which occupies 224 mL at STP. In the light of the above statements, choose the most appropriate answer from the options given below:
Official previous-year question
Held on 22 Jan 2025 · Verified 6 Jul 2026.
Options
- A
Statement I is incorrect but Statement II is correct
- B
Both Statement I and Statement II are correct
- C
Statement I is correct but Statement II is incorrect
- D
Both Statement I and Statement II are incorrect
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