M.wt. of given compound =86

Applying POAC on ' N '
$\begin{aligned}
& \mathrm{n}{\mathrm{X}} \times 2=\mathrm{n}{\mathrm{N}_2} \times 2 \
& \frac{0.42}{86}=\mathrm{n}_{\mathrm{N}_2} \
& \Rightarrow(\text { Volume })_{\mathrm{N}_2} \text { at } \mathrm{STP}=\frac{0.42}{86} \times 22.4 \mathrm{~L} \
& =0.1108 \mathrm{L}=110.8 \mathrm{m} \ell
\end{aligned}$
