Meta–chlorobenzaldehyde will undergo Cannizzaro reaction with 50 to give mchlorobenzoate ion and m−chlorobenzyl alcohol.
Since m−chlorobenzaldehyde does not contain α hydrogen thus with 50 it undergoes the Cannizzaro reaction. The Cannizzaro reaction for the m−chlorobenzaldehyde is given as:
Since it is a disproportionation reaction so one molecule of m−chlorobenzaldehyde is reduced to m−chlorobenzyl alcohol at the cost of others which is oxidized potassium m−chlorobenzoate.



